Array elements in String PHP: How can I print_r the matching elements in the order of the string?

Solution:

The main issue with your code is that youreturn as soon as you find one match, rather than building an array of all the matching strings. In terms of returning the strings in the order they occur in the string, you can use the return value fromstrpos as an array key, and thenksort the result array before returning it:

$string = "hello my dear, how are you doing today ?";
$array = array('are', 'today','hello','bonjour','HolГ ', 'Wassup');

function match($array , $string ) {
    $result = [];
    foreach ($array as $a) {
        if (($pos = strpos($string, $a)) !== false) {
            $result[$pos] = $a;
        }
    }
    ksort($result);
    return array_values($result);
}

print_r(match($array, $string));
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Output:

Array
(
    [0] => hello
    [1] => are
    [2] => today
)
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Demo on 3v4l.org

Note that there is an issue with usingstrpos in that it doesn't consider whether a match is a complete word or not. So for example,match(['are'], 'hare') will return['are']. You can work around this by using in place ofstrpos, and surrounding your search string with\b (a word boundary):

function match($array , $string ) {
    $result = [];
    foreach ($array as $a) {
        if (preg_match("~\b$a\b~", $string, $matches, PREG_OFFSET_CAPTURE)) {
            $result[$matches[0][1]] = $a;
        }
    }
    ksort($result);
    return array_values($result);
}
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print_r(match($array, $string));
print_r(match(['are'], 'hare'));
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Array
(
    [0] => hello
    [1] => are
    [2] => today
)
Array
(
)
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Demo on 3v4l.org

You can further simplify that by using and combining all the elements of$array into a regex alternation:

function match($array , $string ) {
    $result = [];
    foreach ($array as $a) {
        if (preg_match_all('~\b' . implode('\b|\b', $array) . '\b~', $string, $matches)) {
            $result = $matches[0];
        }
    }
    return $result;
}
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Demo on 3v4l.org

Solution:

I can advice next approach:

1. explode string to array of words

2. compare 2 arrays in loop"

   <?php
   $string = "hello my dear, how are you doing today ?";
   $array = array('are', 'today','hello','bonjour','HolГ ', 'Wassup');
   
   function match($array , $string ) {
       $result = [];
       $string_to_arr = explode(' ', $string);
       foreach ($string_to_arr as $s) {
         if (in_array($s, $array)) {
            array_push($result, $s);
         }
       }
   
       return $result;
   }
   
   print_r(match($array , $string ));
   
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You can try live PHP code on PHPize.online

Solution:

You can split your original string into a word array, and then intersect that with your word list.

<?php
$string = "hello my dear, how are you doing today ?";
$array  = array('are', 'today','hello','bonjour','HolГ ', 'Wassup');
$result = array('hello','are','today');

$matched = 
    array_values(
        array_intersect(
            str_word_count($string, 1),
            $array
        )
    );

var_dump($result === $matched);
var_export($matched);
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Output:

bool(true)
array (
  0 => 'hello',
  1 => 'are',
  2 => 'today',
)
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You could swap thestr_word_count($string, 1) forpreg_split('/\b/', $string).

However the above is case sensitive.

You could swap outarray_intersect forarray_uintersect with a case compare.

array_uintersect(str_word_count($string, 1), $array, 'strcasecmp')
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For multibyte case comparisons you are probably better off with thepreg_match route with the appropriate flags or another comparison function.

Solution:

my original answer was bunk just remove the == true