php - codeigniter send id and get database values without refresh
Get the solution ↓↓↓I need to send id and get database values according to the id without page refresh.and display data in my view,
here is my view,
<div>
<a href="javascript:void(0);" class="movie" onclick="getSummary(24)">Click on me</a>
</div>
<script type="text/javascript">
function getSummary(id)
{
$.ajax({
type: "POST",
url: '<?php echo site_url('ajax_controller/getBranchDetails'); ?>',
cache:false,
data: "id=" + id, // appears as $_GET['id'] @ ur backend side
success: function(data) {
// data is ur summary
$('#summary').html(data);
}
});
}
</script>
controller
public function getBranchDetails(){
$b_id = $this->input->post('branch_id');
$this->load->model('ajax_model');
$data['results'] = $this->ajax_model->getRecords($b_id);
//echo json_encode(array('data'=>$data));
}
I need to display $data['results'] in my view
model
<?php
class Ajax_model extends CI_model{
function getRecords($id)
{
$this->load->database();
$query = $this->db->query("SELECT * FROM companydetails WHERE id='$id'");
return $query->result();
}
}
Answer
Solution:
Try this code ,It is working .
<script type="text/javascript">
function getSummary(id)
{
$.post("<?php echo site_url('ajax_controller/getBranchDetails'); ?>",
{branch_id:id},function(data,status){
$('#summary').html(data);
});
}
</script>
Note : Check whether you have included jquery.min.js . If not mention the below code in view part header
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js">
Answer
Solution:
Try this instead:
<script type="text/javascript">
function getSummary(id) {
$.ajax({
type: 'POST',
url: "<?php echo site_url('ajax_controller/getBranchDetails'); ?>", // <-- properly quote this line
cache: false,
data: {branch_id: id}, // <-- provide the branch_id so it will be used as $_POST['branch_id']
dataType: 'JSON', // <-- add json datatype
success: function(data) {
// if you need to present this in a html table,
// likely, you need to use $.each() and build the markup using the json response
$('#summary').html(data);
}
});
}
</script>
Model: (Don't directly use variables inside the query string)
$sql = 'SELECT * FROM companydetails WHERE id = ?';
$query = $this->db->query($sql, array($id));
Controller:
public function getBranchDetails()
{
$b_id = $this->input->post('branch_id', true);
$this->load->model('ajax_model');
$data['results'] = $this->ajax_model->getRecords($b_id);
echo json_encode($data); // <-- uncomment
}
Share solution ↓
Additional Information:
Link To Answer People are also looking for solutions of the problem: foreign key constraint is incorrectly formed laravel
Didn't find the answer?
Our community is visited by hundreds of web development professionals every day. Ask your question and get a quick answer for free.
Similar questions
Find the answer in similar questions on our website.
Write quick answer
Do you know the answer to this question? Write a quick response to it. With your help, we will make our community stronger.