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1 answers
Explanation for PHP preg_match_all matches array print_r
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Solution:
try this so easy to make that
<?php
//$re = "/^(-\\w+\\s*.*)\\n*$/um";
$re = "/^(\\h*(?:-|&)\\h*\w+\\s*.*)\\n*$/um";
$str = "-Give on result\n-Second new text\n-The third text\n\nAnother paragraph without list.\n\n-New list here";
preg_match_all($re, $str, $matches);
echo "<pre>";
print_r($matches);
echo "</pre>";
$i = 0;
echo "<ul>".preg_replace_callback($re,function($mt){return "<li>".$mt[1]."</li>";},$str)."</ul>";
$re = array_filter(preg_split('/\n/', $str));
echo "<pre>";
print_r($re);
echo "</pre>";
Undefined asked
634
votes
Answer
Solution:
I'm trying to replicate this. I usually use this tool https://www.debuggex.com/r/AXpFXcR-ioMLhLCd that explains the Regex conditions in a fancier way.
So far, I think the code evals the regex and only one\n is catched, so the next one passes directly to the output. But I'm trying to confirm this behavior.
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