php - How to show the latest profile picture updated

When the user uploads their first profile picture, there is no problem. But if they uploads a second or even third one, the pictures showed on their profiles do not change if the images have different extensions. Well, just change if:

• If the first uploaded picture was a PNG and the second is a JPG, it will show the JPG. Good.
• If the first or second is a JPG and the new one is a JPEG, the profile will show the JPEG. Good.
• If the first uploaded picture was a JPG and the user uploads a new picture with PNG extension, it would be saved on the Uploads folder, but the profile will show the JPG picture. The same happens if the first one was a JPEG, and it always show the JPEG over the JPG and PNG, no matter what.

So, I get three pictures on the folder (saved every time the user uploads a new profile picture): profile1.png, profile1.jpg, profile1.jpeg. And I want to show the latest uploaded picture for the user and, if possible, prevent the creation of so many (3) files with the same name but different extension.

When the user uploads a new picture with the same extension of the previous one, it overwrites it properly. But, if the extension is different, creates a new image in the folder and mostly won't show as the new picture.

I know I don't explain myself properly, sorry. :c

This is the code to show the avatar:

<?php

require 'includes/database.php';

$id = $_SESSION['userId'];

$sqlImg = "SELECT * FROM u_profiles WHERE user_id='$id'";
$resultImg = mysqli_query($conn, $sqlImg);
if (mysqli_num_rows($resultImg) > 0) {
    while ($rowImg = mysqli_fetch_assoc($resultImg)) {

        if ($rowImg['img_status'] == 0) {
            $fileName = 'Uploads/profile'.$id.'*';
            $fileInfo = glob($fileName);
            $fileExt = explode('.', $fileInfo[0]);
            $fileActualExt = $fileExt[1];
            $avatar = '<img src="Uploads/profile'.$id.'.'.$fileActualExt.'?'.mt_rand().'">';
            echo $avatar;
        } else {
            $default_avatar = '<img src="Uploads/profile-default.png">';
            echo $default_avatar;
        }

    }
}
Copy code

And this is the upload code:

<?php

require_once 'database.php';
session_start();
$id = $_SESSION['userId'];

if (isset($_POST['file-submit'])) {
    $file = $_FILES['file'];

    $fileName = $_FILES['file']['name'];
    $fileTmpName = $_FILES['file']['tmp_name'];
    $fileSize = $_FILES['file']['size'];
    $fileError = $_FILES['file']['error'];
    $fileType = $_FILES['file']['type'];

    $fileExt = explode('.', $fileName);
    $fileActualExt = strtolower(end($fileExt));

    $allowed = array('jpg', 'jpeg', 'png');

    if (in_array($fileActualExt, $allowed)) {

        if ($fileError === 0) {

            if ($fileSize < 1000000) {

                $fileNameNew = "profile".$id.".".$fileActualExt;
                $fileDestination = '../Uploads/'.$fileNameNew;
                move_uploaded_file($fileTmpName, $fileDestination);

                $sql = "UPDATE u_profiles SET img_status=0 WHERE user_id='$id';";
                $result = mysqli_query($conn, $sql);
                header("Location: ../edit-profile.php?uploads=success");

            } else {
                header("Location: ../edit-profile.php?error=avatarsize");
            }

        } else {
            echo "There was a problem uploading your file.";
        }

    } else {
        echo "You cannot upload this type of file.";
    }

} else {
    header("Location: ../index.php");
    exit();
}
Copy code

Didn't find the answer?

Our community is visited by hundreds of web development professionals every day. Ask your question and get a quick answer for free.