Is there an easy way to receive Http POST request in python, like in php?

Solution:

In Python the easier way to getPOST is to useFlask and run it with built-in server.

script.py

from flask import Flask, request

app = Flask(__name__)

@app.route('/', methods=['POST', 'GET'])
def index():
   if request.method == 'POST':
      value1 = request.form.get('value1')
      value2 = request.form.get('value2')
      return 'OK'
   else:
      return 'Use POST requests'

if __name__ == '__main__':
    #app.debug = True
    app.run(host='0.0.0.0', port=8000)
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and run as

python script.py
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and it will run server on port8000 so you can connecthttp://myserver:8000/

But if you already runApache/nginx withPHP then this makes problem.

You can't run both servers on the same port80. It would need to run all withApache.

PHP was created for web pages andApache has preinstalled module to runPHP (and to run PHP frameworks likeLaravel) but usually it doesn't have module forPython. It may install module to run Python or other module to run CGI or FastCGI (which means any executable script - Python, Perl, Bash, and even compiled C/C++) but this is very old method which needs different modules in Python - so rather it can't runFlask - and probably nobody use it.Flask,Django,Bottle is simpler to write code, has many built-in functions and code is cleaner and better organized - like in PHP frameworks.

Flask and other Python web frameworks (likeDjango,Bottle) are created to run with WSGI severs likeGunicorn. They use eventuallyApache only asproxy-server and to serve static files like images, CSS. So to use Flask/Django on external server you would have to find server which is configured forFlask,Django, etc. like PythonAnywhere

InPHP you can mix all in one file - code, HTML, SQL - so it can make big mess and people created frameworks likeLaravel to make it cleaner and better organized. InPython you use at start framework so you would have to compareFlask with PHP frameworks but not with pure PHP.