PHP - If array contains

Solution:

Try something like this , to check existence of each item

 <?php 
 if (in_array('nl', $languagevalue)) { 
     //NL image
 }
 if (in_array('en', $languagevalue)) { 
     //en image
 }
 if (in_array('de', $languagevalue)) { 
     //de image
 }
 if (in_array('it', $languagevalue)) { 
     //it image
 }
 ?>
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Solution:

I would actually create another array with the flag images by iterating over the$languagevalue array:

$flags = [];
foreach($languagevalue as $lang) {
  $flags[] = "$lang-flag";
}
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Now you can iterate over$flags.

This assumes you can derive the flag name directly from the language name. If that's not the case, you'll have to use something like aswitch statement to map the language name to the flag image name.

Solution:

You can implode the values with the html of the end and begining of the IMG tag.
This way you don't need to loop or check if the value is in the array. The html is generated automatically.

$languagevalue = ['NL', 'EN', 'DE'];

echo '<img src="images/' . implode('-flag.png" alt=""/> <img src="images/' ,$languagevalue) . '-flag.png" alt=""/>';
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https://3v4l.org/D2IMg

Output:

<img src="images/NL-flag.png" alt=""/> 
<img src="images/EN-flag.png" alt=""/> 
<img src="images/DE-flag.png" alt=""/>
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Added new lines for clarifying