php - Set a variable using an array value based on another value in the same array

Solution:

{-code-1}
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Set foreach loop on the array, set the values, loop through values, find the key value,$index === 'is_captain' and make sure it is set to1 ->$data === '1'. If this is true define your variable.

foreach($arr as $value){
  foreach($value as $index => $data){
    if($index === 'is_captain' && $data === 1){
      $element = $value['element'];
      echo $element; // $element now holds the value where key = `element` if 'is_captain' is equal to `1`
    }
  }  
}
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In your code, change the$key['is_captain'] to$key === 'is_captain' then look for its value if it is a match with in that same conditional.

If the key is equal to target keyis_captain and that keys value is equal to1 get the value of the key set aselement and assign it to your variable:

    if ($key === 'is_captain' && $val === 1)){
      $variable = $value['element'];
    }
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Solution:

I was set in the right direction, so thanks immensely to the contributor for the help.

My original question didn't make clear that I was working with a nested array. My array snippet didn't show that. I've learned a lesson about completeness. (I'm new here).

Once I wrote the code block to handle the nested array and modified the conditional slightly, I was successful. Here's the final code which works:

$x = 0; 
$captainsArr = array($fpl_team_picks['picks']);

    foreach($captainsArr[$x++] as $value) {
        if (is_array($value)){
            foreach ($value as $index => $data) {
                if ($index === 'is_captain' && $data == 1){
                    $captain = $value['element'];
                }
            }
        }
    }
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