Get php results with jquery ajax
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Solution:
Are you including your php file that you use for your ajax call at the top of the page? If so you dont need to. That would cause the data to dump at the top.
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EDIT TO ANSWER QUESTION
<div id="product-list">
<?php include 'products.php' ?>
</div>
Your ajax function will now overwrite the php content when it runs and outputs to #product-list
Answer
Solution:
If you mean you want to avoid showing the header and body tags, just the contents, you need to detect when the request isAJAX atPHP side.
Some pseudo-code is:
IF (!IS_AJAX)
HTML
HEADER
BODY
ENDIF
CONTENTS
IF (!IS_AJAX)
/BODY
/HTML
ENDIF
Search for HTTP_X_REQUESTED_WITH here at stackoverflow
Answer
Solution:
Your question isn't exactly clear, but it sounds like you only want to use PART of the response data. If that's the case, then there's 2 ways to go about it:
First, you can check on the PHP side if it's being requested via AJAX. This is the solution I'd use, since it prevents useless data being transferred to the client:
define('IS_AJAX', isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest');
...
if(!IS_AJAX) {
// anything here will NOT be sent in response to ajax requests
}
Alternatively, you can mark the part of the response data you wish to use with an ID, then search the returned data for that id:
<h1>Don't care about this</h1> <div id="use_this">This is the useful data.</div>
Then for your ajax response callback:
success = function(data) {
data = $(data).find('#use_this');
// do whatever
}
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